VIDEO solution: Answer: 1. Prove that G/H is isomorphic to a subgroup of S5 (the symmetric group on 5 elements). 2. Given that G is simple (has no non-trivial normal subgroups other
Alternating Group -- from Wolfram MathWorld
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Solved Take G = A_4, the alternating group on 4 letters, and | Chegg.com
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abstract algebra - $A_n$ is simple if $n \ge 5$ - Mathematics Stack Exchange
1) (The infinite alternating group) Let N = {1,2, | Chegg.com
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An is simple(but not so simple) for all n ≥ 5| Restricted(infinite) Alternating group is simple - YouTube
Math 3121 Abstract Algebra I Lecture 14 Sections ppt download
PDF) Representations of the alternating group which are irreducible over subgroups. II
